函数逻辑报告 |
Source Code:include\linux\fscrypt.h |
Create Date:2022-07-29 10:32:14 |
Last Modify:2020-03-12 14:18:49 | Copyright©Brick |
首页 | 函数Tree |
注解内核,赢得工具 | 下载SCCT | English |
函数名称:scrypt_prepare_lookup - prepare to lookup a name in a possibly-encrypted directory*@dir: directory being searched*@dentry: filename being looked up*@fname: (output) the name to use to search the on-disk directory* Prepare for ->lookup() in a directory
函数原型:static inline int fscrypt_prepare_lookup(struct inode *dir, struct dentry *dentry, struct fscrypt_name *fname)
返回类型:int
参数:
类型 | 参数 | 名称 |
---|---|---|
struct inode * | dir | |
struct dentry * | dentry | |
struct fscrypt_name * | fname |
641 | 如果IS_ENCRYPTED(dir)则返回:__fscrypt_prepare_lookup(dir, dentry, fname) |
648 | 返回:0 |
源代码转换工具 开放的插件接口 | X |
---|---|
支持:c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现:逻辑报告 代码生成和批量转换代码 |