函数逻辑报告 |
Source Code:include\linux\fscrypt.h |
Create Date:2022-07-29 10:32:14 |
| Last Modify:2020-03-12 14:18:49 | Copyright©Brick |
| 首页 | 函数Tree |
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函数名称:__fscrypt_prepare_lookup
函数原型:static inline int __fscrypt_prepare_lookup(struct inode *dir, struct dentry *dentry, struct fscrypt_name *fname)
返回类型:int
参数:
| 类型 | 参数 | 名称 |
|---|---|---|
| struct inode * | dir | |
| struct dentry * | dentry | |
| struct fscrypt_name * | fname |
| 497 | 返回:负EOPNOTSUPP |
| 名称 | 描述 |
|---|---|
| fscrypt_prepare_lookup | scrypt_prepare_lookup - prepare to lookup a name in a possibly-encrypted directory*@dir: directory being searched*@dentry: filename being looked up*@fname: (output) the name to use to search the on-disk directory* Prepare for ->lookup() in a directory |
| 源代码转换工具 开放的插件接口 | X |
|---|---|
| 支持:c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现:逻辑报告 代码生成和批量转换代码 |