函数逻辑报告 |
Source Code:include\linux\fscrypt.h |
Create Date:2022-07-29 10:32:13 |
Last Modify:2020-03-12 14:18:49 | Copyright©Brick |
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函数名称:fscrypt_has_permitted_context
函数原型:static inline int fscrypt_has_permitted_context(struct inode *parent, struct inode *child)
返回类型:int
参数:
类型 | 参数 | 名称 |
---|---|---|
struct inode * | parent | |
struct inode * | child |
352 | 返回:0 |
名称 | 描述 |
---|---|
fscrypt_file_open | scrypt_file_open - prepare to open a possibly-encrypted regular file*@inode: the inode being opened*@filp: the struct file being set up* Currently, an encrypted regular file can only be opened if its encryption key |
__fscrypt_prepare_link | |
__fscrypt_prepare_rename |
源代码转换工具 开放的插件接口 | X |
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支持:c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现:逻辑报告 代码生成和批量转换代码 |