函数逻辑报告 |
Source Code:fs\crypto\hooks.c |
Create Date:2022-07-29 10:57:09 |
Last Modify:2020-03-12 14:18:49 | Copyright©Brick |
首页 | 函数Tree |
注解内核,赢得工具 | 下载SCCT | English |
函数名称:__fscrypt_prepare_link
函数原型:int __fscrypt_prepare_link(struct inode *inode, struct inode *dir, struct dentry *dentry)
返回类型:int
参数:
类型 | 参数 | 名称 |
---|---|---|
struct inode * | inode | |
struct inode * | dir | |
struct dentry * | dentry |
57 | err等于scrypt_require_key - require an inode's encryption key*@inode: the inode we need the key for* If the inode is encrypted, set up its encryption key if not already done |
65 | 如果非fscrypt_has_permitted_context(dir, inode)则返回:负EXDEV |
68 | 返回:0 |
名称 | 描述 |
---|---|
fscrypt_prepare_link | scrypt_prepare_link - prepare to link an inode into a possibly-encrypted directory*@old_dentry: an existing dentry for the inode being linked*@dir: the target directory*@dentry: negative dentry for the target filename* A new link can only be added to an |
源代码转换工具 开放的插件接口 | X |
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支持:c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现:逻辑报告 代码生成和批量转换代码 |