函数逻辑报告 |
Source Code:security\keys\process_keys.c |
Create Date:2022-07-27 19:56:41 |
| Last Modify:2020-03-12 14:18:49 | Copyright©Brick |
| 首页 | 函数Tree |
| 注解内核,赢得工具 | 下载SCCT | English |
函数名称:Get the user session keyring if it exists, but don't create it if it* doesn't.
函数原型:struct key *get_user_session_keyring_rcu(const struct cred *cred)
返回类型:struct key
参数:
| 类型 | 参数 | 名称 |
|---|---|---|
| const struct cred * | cred |
| 201 | 如果非reg_keyring则返回:NULL |
| 208 | session_keyring_r等于keyring_search_rcu - Search a keyring tree for a matching key under RCU*@keyring_ref: A pointer to the keyring with possession indicator |
| 210 | 如果是错误则返回:NULL |
| 212 | 返回:key_ref_to_ptr(session_keyring_r) |
| 名称 | 描述 |
|---|---|
| search_cred_keyrings_rcu | Search the process keyrings attached to the supplied cred for the first* matching key under RCU conditions (the caller must be holding the RCU read* lock) |
| 源代码转换工具 开放的插件接口 | X |
|---|---|
| 支持:c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现:逻辑报告 代码生成和批量转换代码 |