函数逻辑报告 |
Source Code:security\keys\keyctl.c |
Create Date:2022-07-27 19:54:12 |
Last Modify:2020-03-18 07:59:52 | Copyright©Brick |
首页 | 函数Tree |
注解内核,赢得工具 | 下载SCCT | English |
函数名称:Join a (named) session keyring.* Create and join an anonymous session keyring or join a named session* keyring, creating it if necessary. A named session keyring must have Search* permission for it to be joined. Session keyrings without this permit will
函数原型:long keyctl_join_session_keyring(const char __user *_name)
返回类型:long
参数:
类型 | 参数 | 名称 |
---|---|---|
const char __user * | _name |
295 | name = NULL |
296 | 如果_name则 |
298 | 如果是错误则 |
304 | 如果name[0]恒等于'.'则转到:error_name |
309 | ret等于Join the named keyring as the session keyring if possible else attempt to* create a new one of that name and join that |
310 | error_name : |
311 | 释放内存 |
312 | error : |
313 | 返回:ret |
名称 | 描述 |
---|---|
SYSCALL_DEFINE5 | The key control system call |
COMPAT_SYSCALL_DEFINE5 | The key control system call, 32-bit compatibility version for 64-bit archs |
源代码转换工具 开放的插件接口 | X |
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支持:c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现:逻辑报告 代码生成和批量转换代码 |