函数逻辑报告 |
Source Code:security\commoncap.c |
Create Date:2022-07-27 20:09:51 |
Last Modify:2020-03-12 14:18:49 | Copyright©Brick |
首页 | 函数Tree |
注解内核,赢得工具 | 下载SCCT | English |
函数名称:Determine whether the inheritable capabilities are limited to the old* permitted set. Returns 1 if they are limited, 0 if they are not.
函数原型:static inline int cap_inh_is_capped(void)
返回类型:int
参数:无
226 | 返回:1 |
名称 | 描述 |
---|---|
cap_capset | ap_capset - Validate and apply proposed changes to current's capabilities*@new: The proposed new credentials; alterations should be made here*@old: The current task's current credentials*@effective: A pointer to the proposed new effective capabilities |
源代码转换工具 开放的插件接口 | X |
---|---|
支持:c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现:逻辑报告 代码生成和批量转换代码 |