函数逻辑报告 |
Source Code:security\apparmor\label.c |
Create Date:2022-07-27 21:45:55 |
Last Modify:2020-03-12 14:18:49 | Copyright©Brick |
首页 | 函数Tree |
注解内核,赢得工具 | 下载SCCT | English |
函数名称:sure stacks with components like* :ns:A//&B* have :ns: applied to both 'A' and 'B' by making the lookup relative* to the base if the lookup specifies an ns, else making the stacked lookup* relative to the last embedded ns in the string.
函数原型:static struct aa_profile *fqlookupn_profile(struct aa_label *base, struct aa_label *currentbase, const char *str, size_t n)
返回类型:struct aa_profile
参数:
类型 | 参数 | 名称 |
---|---|---|
struct aa_label * | base | |
struct aa_label * | currentbase | |
const char * | str | |
size_t | n |
1837 | first等于skipn_spaces - Removes leading whitespace from @str.*@str: The string to be stripped.* Returns a pointer to the first non-whitespace character in @str.* if all whitespace will return NULL |
1842 | 返回:aa_fqlookupn_profile(currentbase, str, n) |
名称 | 描述 |
---|---|
aa_label_strn_parse | aa_label_strn_parse - parse, validate and convert a text string to a label*@base: base label to use for lookups (NOT NULL)*@str: null terminated text string (NOT NULL)*@n: length of str to parse, will stop at \0 if encountered before n*@gfp: allocation |
源代码转换工具 开放的插件接口 | X |
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支持:c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现:逻辑报告 代码生成和批量转换代码 |