函数逻辑报告 |
Source Code:security\apparmor\label.c |
Create Date:2022-07-27 21:44:39 |
Last Modify:2020-03-12 14:18:49 | Copyright©Brick |
首页 | 函数Tree |
注解内核,赢得工具 | 下载SCCT | English |
函数名称:aa_label_find - find label @label in label set*@label: label to find (NOT NULL)* Requires: caller to hold a valid ref on l* Returns: refcounted @label if @label is in tree* refcounted label that is equiv to @label in tree* else NULL if @label or equiv is
函数原型:struct aa_label *aa_label_find(struct aa_label *label)
返回类型:struct aa_label
参数:
类型 | 参数 | 名称 |
---|---|---|
struct aa_label * | label |
源代码转换工具 开放的插件接口 | X |
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支持:c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现:逻辑报告 代码生成和批量转换代码 |