函数逻辑报告 |
Source Code:security\apparmor\include\policy_ns.h |
Create Date:2022-07-27 21:20:47 |
Last Modify:2020-03-12 14:18:49 | Copyright©Brick |
首页 | 函数Tree |
注解内核,赢得工具 | 下载SCCT | English |
函数名称:__aa_findn_ns - find a namespace on a list by @name*@head: list to search for namespace on (NOT NULL)*@name: name of namespace to look for (NOT NULL)*@n: length of @name* Returns: unrefcounted namespace* Requires: rcu_read_lock be held
函数原型:static inline struct aa_ns *__aa_findn_ns(struct list_head *head, const char *name, size_t n)
返回类型:struct aa_ns
参数:
类型 | 参数 | 名称 |
---|---|---|
struct list_head * | head | |
const char * | name | |
size_t | n |
名称 | 描述 |
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ns_rmdir_op | |
aa_findn_ns | aa_findn_ns - look up a profile namespace on the namespace list*@root: namespace to search in (NOT NULL)*@name: name of namespace to find (NOT NULL)*@n: length of @name* Returns: a refcounted namespace on the list, or NULL if no namespace |
__aa_lookupn_ns | __aa_lookupn_ns - lookup the namespace matching @hname*@base: base list to start looking up profile name from (NOT NULL)*@hname: hierarchical ns name (NOT NULL)*@n: length of @hname* Requires: rcu_read_lock be held* Returns: unrefcounted ns pointer or |
__aa_find_ns |
源代码转换工具 开放的插件接口 | X |
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支持:c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现:逻辑报告 代码生成和批量转换代码 |