函数逻辑报告 |
Source Code:mm\page_alloc.c |
Create Date:2022-07-27 16:38:37 |
| Last Modify:2020-03-12 14:18:49 | Copyright©Brick |
| 首页 | 函数Tree |
| 注解内核,赢得工具 | 下载SCCT | English |
函数名称：Returns the number of pages that arch has reserved but* is not known to alloc_large_system_hash().
函数原型：static unsigned long __init arch_reserved_kernel_pages(void)
返回类型：unsigned long
参数：无
| 8032 | 返回:0 |
| 名称 | 描述 |
|---|---|
| alloc_large_system_hash | allocate a large system hash table from bootmem* - it is assumed that the hash table must contain an exact power-of-2* quantity of entries* - limit is the number of hash buckets, not the total allocation size |
| 源代码转换工具 开放的插件接口 | X |
|---|---|
| 支持：c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现：逻辑报告 代码生成和批量转换代码 |