函数逻辑报告 |
Source Code:mm\cma.c |
Create Date:2022-07-27 18:06:54 |
Last Modify:2020-03-12 14:18:49 | Copyright©Brick |
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函数名称:Find the offset of the base PFN from the specified align_order.* The value returned is represented in order_per_bits.
函数原型:static unsigned long cma_bitmap_aligned_offset(const struct cma *cma, unsigned int align_order)
返回类型:unsigned long
参数:
类型 | 参数 | 名称 |
---|---|---|
const struct cma * | cma | |
unsigned int | align_order |
73 | 返回:base_pfn按位与1UL左移align_order位的值减1的值右移 Order of pages represented by one bit 位 |
名称 | 描述 |
---|---|
cma_alloc | ma_alloc() - allocate pages from contiguous area*@cma: Contiguous memory region for which the allocation is performed |
源代码转换工具 开放的插件接口 | X |
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支持:c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现:逻辑报告 代码生成和批量转换代码 |