函数逻辑报告

Linux Kernel

v5.5.9

Brick Technologies Co., Ltd

Source Code:lib\objagg.c Create Date:2022-07-27 08:22:28
Last Modify:2020-03-12 14:18:49 Copyright©Brick
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函数名称:objagg_obj_is_root

函数原型:static bool objagg_obj_is_root(const struct objagg_obj *objagg_obj)

返回类型:bool

参数:

类型参数名称
const struct objagg_obj *objagg_obj
103  返回:非 if the object is nested, this * holds pointer to parent, otherwise NULL
调用者
名称描述
objagg_obj_root_privbjagg_obj_root_priv - obtains root private for an object*@objagg_obj: objagg object instance* Note: all locking must be provided by the caller
objagg_obj_delta_privbjagg_obj_delta_priv - obtains delta private for an object*@objagg_obj: objagg object instance* Note: all locking must be provided by the caller.* Returns user private delta pointer or NULL in case the passed* object is root.
objagg_obj_parent_lookup_assign
objagg_obj_fini
objagg_stats_getbjagg_stats_get - obtains stats of the objagg instance*@objagg: objagg instance* Note: all locking must be provided by the caller.* The returned structure contains statistics of all object* currently in use, ordered by following rules: