函数逻辑报告

Linux Kernel

v5.5.9

Brick Technologies Co., Ltd

Source Code:lib\kstrtox.c Create Date:2022-07-27 07:23:33
Last Modify:2020-03-12 14:18:49 Copyright©Brick
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函数名称：Convert non-negative integer string representation in explicitly given radix* to an integer.* Return number of characters consumed maybe or-ed with overflow bit.* If overflow occurs, result integer (incorrect) is still returned.

函数原型：unsigned int _parse_integer(const char *s, unsigned int base, unsigned long long *p)

返回类型：unsigned int

参数：

类型参数名称
const char *s
unsigned intbase
unsigned long long *p
53  res等于0
54  rv等于0
55  当1循环
56  c等于s
57  lc等于c按位或0x20
60  如果'0'小于等于c且c小于等于'9'则val等于c减'0'
62  否则如果'a'小于等于lc且lc小于等于'f'则val等于lc减'a'加10
64  否则退出
67  如果val大于等于base则退出
73  如果此条件成立可能性小(为编译器优化)(res & (~0ull << 60))则
74  如果res大于div_u64 - unsigned 64bit divide with 32bit divisor*@dividend: unsigned 64bit dividend*@divisor: unsigned 32bit divisor* This is the most common 64bit divide and should be used if possible,* as many 32bit archs can optimize this variant better than a full 则rv或等于KSTRTOX_OVERFLOW
77  res等于res乘base加val
78  rv自加
79  s自加
81  p等于res
82  返回:rv
调用者
名称描述
simple_strtoull转换字符串为无符号长整形
strtoul_lenientstrtoul_lenient - parse an ASCII formatted integer from a buffer and only* fail on overflow*@cp: kernel buffer containing the string to parse*@endp: pointer to store the trailing characters*@base: the base to use*@res: where the parsed integer will be
bitmap_getnum
_kstrtoull