函数逻辑报告 |
Source Code:lib\bitmap.c |
Create Date:2022-07-27 07:17:30 |
Last Modify:2020-03-12 14:18:49 | Copyright©Brick |
首页 | 函数Tree |
注解内核,赢得工具 | 下载SCCT | English |
函数名称:map_ord_to_pos - find position of n-th set bit in bitmap*@buf: pointer to bitmap*@ord: ordinal bit position (n-th set bit, n >= 0)*@nbits: number of valid bit positions in @buf* Map the ordinal offset of bit @ord in @buf to its position in @buf.
函数原型:unsigned int bitmap_ord_to_pos(const unsigned long *buf, unsigned int ord, unsigned int nbits)
返回类型:unsigned int
参数:
类型 | 参数 | 名称 |
---|---|---|
const unsigned long * | buf | |
unsigned int | ord | |
unsigned int | nbits |
768 | 返回:pos |
名称 | 描述 |
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bitmap_remap | map_remap - Apply map defined by a pair of bitmaps to another bitmap*@dst: remapped result*@src: subset to be remapped*@old: defines domain of map*@new: defines range of map*@nbits: number of bits in each of these bitmaps* Let @old and @new define a |
bitmap_bitremap | map_bitremap - Apply map defined by a pair of bitmaps to a single bit*@oldbit: bit position to be mapped*@old: defines domain of map*@new: defines range of map*@bits: number of bits in each of these bitmaps* Let @old and @new define a mapping of bit |
node_random | Return the bit number of a random bit set in the nodemask.* (returns NUMA_NO_NODE if nodemask is empty) |
源代码转换工具 开放的插件接口 | X |
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支持:c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现:逻辑报告 代码生成和批量转换代码 |