函数逻辑报告

Linux Kernel

v5.5.9

Brick Technologies Co., Ltd

Source Code:kernel\resource.c Create Date:2022-07-27 10:05:15
Last Modify:2022-05-22 11:14:39 Copyright©Brick
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函数名称：source_alignment - calculate resource's alignment*@res: resource pointer* Returns alignment on success, 0 (invalid alignment) on failure.

函数原型：resource_size_t resource_alignment(struct resource *res)

返回类型：resource_size_t

参数：

类型参数名称
struct resource *res
1093  当: & == size indicates alignment
1094  返回:resource_size(res)
1095  当: & == start field is alignment
1096  返回:start
1097  默认
1098  返回:0