函数逻辑报告 |
Source Code:kernel\rcu\tree.c |
Create Date:2022-07-27 11:25:36 |
Last Modify:2020-03-12 14:18:49 | Copyright©Brick |
首页 | 函数Tree |
注解内核,赢得工具 | 下载SCCT | English |
函数名称:Let the RCU core know that this CPU has gone through the scheduler,* which is a quiescent state
函数原型:void rcu_momentary_dyntick_idle(void)
返回类型:void
参数:无
371 | raw_cpu_write(rcu_need_heavy_qs, false) |
372 | special等于atomic_add_return(2 * RCU_DYNTICK_CTRL_CTR, & dynticks) |
375 | WARN_ON_ONCE(!(special & RCU_DYNTICK_CTRL_CTR)) |
名称 | 描述 |
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rcu_torture_fwd_prog_cbfree | Free all callbacks on the rcu_fwd_cb_head list, either because the* test is over or because we hit an OOM event. |
rcu_torture_fwd_prog_cr | Carry out call_rcu() forward-progress testing. |
multi_cpu_stop | This is the cpu_stop function which stops the CPU. |
rcu_all_qs | Register an urgently needed quiescent state. If there is an* emergency, invoke rcu_momentary_dyntick_idle() to do a heavy-weight* dyntick-idle quiescent state visible to other CPUs, which will in |
rcu_note_context_switch | Note a PREEMPT=n context switch. The caller must have disabled interrupts. |
源代码转换工具 开放的插件接口 | X |
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支持:c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现:逻辑报告 代码生成和批量转换代码 |