函数逻辑报告 |
Source Code:kernel\rcu\rcu.h |
Create Date:2022-07-27 11:17:55 |
Last Modify:2022-05-19 07:39:19 | Copyright©Brick |
首页 | 函数Tree |
注解内核,赢得工具 | 下载SCCT | English |
函数名称:Reclaim the specified callback, either by invoking it (non-lazy case)* or freeing it directly (lazy case). Return true if lazy, false otherwise.
函数原型:static inline bool __rcu_reclaim(const char *rn, struct callback_head *head)
返回类型:bool
参数:
类型 | 参数 | 名称 |
---|---|---|
const char * | rn | |
struct callback_head * | head |
212 | rcu_lock_acquire( & rcu_callback_map) |
216 | rcu_lock_release( & rcu_callback_map) |
217 | 返回:true |
218 | 否则 |
名称 | 描述 |
---|---|
rcu_do_batch | Invoke any RCU callbacks that have made it to the end of their grace* period. Thottle as specified by rdp->blimit. |
rcu_process_callbacks | Invoke the RCU callbacks whose grace period has elapsed. |
源代码转换工具 开放的插件接口 | X |
---|---|
支持:c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现:逻辑报告 代码生成和批量转换代码 |