函数逻辑报告 |
Source Code:kernel\module.c |
Create Date:2022-07-27 11:58:22 |
Last Modify:2020-03-12 14:18:49 | Copyright©Brick |
首页 | 函数Tree |
注解内核,赢得工具 | 下载SCCT | English |
函数名称:Search for module by name: must hold module_mutex (or preempt disabled* for read-only access).
函数原型:static struct module *find_module_all(const char *name, size_t len, bool even_unformed)
返回类型:struct module
参数:
类型 | 参数 | 名称 |
---|---|---|
const char * | name | |
size_t | len | |
bool | even_unformed |
623 | 如果非even_unformed且state恒等于MODULE_STATE_UNFORMED则继续下一循环 |
628 | 返回:NULL |
名称 | 描述 |
---|---|
find_module | |
finished_loading | Is this module of this name done loading? No locks held. |
add_unformed_module | We try to place it in the list now to make sure it's unique before* we dedicate too many resources. In particular, temporary percpu* memory exhaustion. |
源代码转换工具 开放的插件接口 | X |
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支持:c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现:逻辑报告 代码生成和批量转换代码 |