函数逻辑报告 |
Source Code:kernel\module.c |
Create Date:2022-07-27 11:59:31 |
Last Modify:2020-03-12 14:18:49 | Copyright©Brick |
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函数名称:check_module_license_and_versions
函数原型:static int check_module_license_and_versions(struct module *mod)
返回类型:int
参数:
类型 | 参数 | 名称 |
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struct module * | mod |
3328 | 如果字符串比较恒等于0则add_taint_module(mod, This cannot be an enum because some may be used in assembly source. , LOCKDEP_NOW_UNRELIABLE) |
3333 | 如果字符串比较恒等于0则add_taint_module(mod, This cannot be an enum because some may be used in assembly source. , LOCKDEP_NOW_UNRELIABLE) |
3337 | 如果非prev_taint且test_taint(This cannot be an enum because some may be used in assembly source. )则打印警告信息("%s: module license taints kernel.\n", Unique handle for this module ) |
3353 | 返回:0 |
名称 | 描述 |
---|---|
load_module | Allocate and load the module: note that size of section 0 is alwayszero, and we rely on this for optional sections. |
源代码转换工具 开放的插件接口 | X |
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支持:c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现:逻辑报告 代码生成和批量转换代码 |