| 函数逻辑报告 | 
| Source Code: kernel\hung_task.c | Create Date:2022-07-27 12:49:42 | 
| Last Modify:2020-03-12 14:18:49 | Copyright©Brick | 
| 首页 | 函数Tree | 
| 注解内核,赢得工具 | 下载SCCT | English | 
函数名称:Check whether a TASK_UNINTERRUPTIBLE does not get woken up for* a really long time (120 seconds). If that happens, print out* a warning.
函数原型:static void check_hung_uninterruptible_tasks(unsigned long timeout)
返回类型:void
参数:
| 类型 | 参数 | 名称 | 
|---|---|---|
| unsigned long | timeout | 
| 176 | last_break等于jiffies | 
| 183 | 如果test_taint(TAINT_DIE)或did_panic则返回 | 
| 186 | hung_task_show_lock = false | 
| 194 | last_break等于jiffies | 
| 197 | 如果任务状态恒等于深度睡眠态则check_hung_task(t, timeout) | 
| 200 | unlock : | 
| 204 | 如果hung_task_call_panic则 | 
| 名称 | 描述 | 
|---|---|
| watchdog | kthread which checks for tasks stuck in D state | 
| 源代码转换工具 开放的插件接口 | X | 
|---|---|
| 支持:c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现:逻辑报告 代码生成和批量转换代码 |