函数逻辑报告 |
Source Code:kernel\bpf\verifier.c |
Create Date:2022-07-27 14:17:58 |
| Last Modify:2022-05-19 20:02:10 | Copyright©Brick |
| 首页 | 函数Tree |
| 注解内核,赢得工具 | 下载SCCT | English |
函数名称：Return true if it's OK to have the same insn return a different type.
函数原型：static bool reg_type_mismatch_ok(enum bpf_reg_type type)
返回类型：bool
参数：
| 类型 | 参数 | 名称 |
|---|---|---|
| enum bpf_reg_type | type |
| 7703 | 当:type恒等于g points to bpf_context |
| 7704 | 当:type恒等于g points to struct bpf_sock |
| 7706 | 当:type恒等于g points to sock_common |
| 7707 | 当:type恒等于g points to sock_common or NULL |
| 7708 | 当:type恒等于g points to struct tcp_sock |
| 7710 | 当:type恒等于g points to struct xdp_sock |
| 7711 | 当:type恒等于g points to kernel struct |
| 7712 | 返回:false |
| 7713 | 默认 |
| 7714 | 返回:true |
| 名称 | 描述 |
|---|---|
| reg_type_mismatch | If an instruction was previously used with particular pointer types, then we* need to be careful to avoid cases such as the below, where it may be ok* for one branch accessing the pointer, but not ok for the other branch:* R1 = sock_ptr* goto X;* |
| 源代码转换工具 开放的插件接口 | X |
|---|---|
| 支持：c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现：逻辑报告 代码生成和批量转换代码 |