函数逻辑报告 |
Source Code:include\linux\kobject.h |
Create Date:2022-07-27 06:45:13 |
| Last Modify:2020-03-12 14:18:49 | Copyright©Brick |
| 首页 | 函数Tree |
| 注解内核,赢得工具 | 下载SCCT | English |
函数名称：kobject_has_children - Returns whether a kobject has children.*@kobj: the object to test* This will return whether a kobject has other kobjects as children.* It does NOT account for the presence of attribute files, only sub* directories
函数原型：static inline bool kobject_has_children(struct kobject *kobj)
返回类型：bool
参数：
| 类型 | 参数 | 名称 |
|---|---|---|
| struct kobject * | kobj |
| 134 | WARN_ON_ONCE(kref_read( & 对象引用计数) == 0) |
| 136 | 返回: sysfs directory entry 且subdirs |
| 源代码转换工具 开放的插件接口 | X |
|---|---|
| 支持：c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现：逻辑报告 代码生成和批量转换代码 |