函数逻辑报告 |
Source Code:include\linux\freezer.h |
Create Date:2022-07-27 06:56:42 |
| Last Modify:2020-03-12 14:18:49 | Copyright©Brick |
| 首页 | 函数Tree |
| 注解内核,赢得工具 | 下载SCCT | English |
函数名称：freezer_should_skip
函数原型：static inline int freezer_should_skip(struct task_struct *p)
返回类型：int
参数：
| 类型 | 参数 | 名称 |
|---|---|---|
| struct task_struct * | p |
| 276 | 返回:0 |
| 名称 | 描述 |
|---|---|
| try_to_freeze_tasks | |
| freeze_task | ze_task - send a freeze request to given task*@p: task to send the request to* If @p is freezing, the freeze request is sent either by sending a fake* signal (if it's not a kernel thread) or waking it up (if it's a kernel* thread) |
| update_if_frozen | pdate_if_frozen - update whether a cgroup finished freezing*@css: css of interest* Once FREEZING is initiated, transition to FROZEN is lazily updated by* calling this function |
| 源代码转换工具 开放的插件接口 | X |
|---|---|
| 支持：c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现：逻辑报告 代码生成和批量转换代码 |