函数逻辑报告 |
Source Code:include\linux\ext2_fs.h |
Create Date:2022-07-27 15:19:52 |
Last Modify:2020-03-12 14:18:49 | Copyright©Brick |
首页 | 函数Tree |
注解内核,赢得工具 | 下载SCCT | English |
函数名称:ext2_image_size
函数原型:static inline u64 ext2_image_size(void *ext2_sb)
返回类型:u64
参数:
类型 | 参数 | 名称 |
---|---|---|
void * | ext2_sb |
37 | 如果*p加EXT2_SB_MAGIC_OFFSET的和不等于cpu_to_le16(EXT2_SUPER_MAGIC)则返回:0 |
39 | 返回:le32_to_cpup((__le32 * )(p + EXT2_SB_BLOCKS_OFFSET))左移le32_to_cpup((__le32 * )(p + EXT2_SB_BSIZE_OFFSET))位 |
名称 | 描述 |
---|---|
identify_ramdisk_image | This routine tries to find a RAM disk image to load, and returns the* number of blocks to read for a non-compressed image, 0 if the image* is a compressed image, and -1 if an image with the right magic* numbers could not be found |
源代码转换工具 开放的插件接口 | X |
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支持:c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现:逻辑报告 代码生成和批量转换代码 |