函数逻辑报告 |
Source Code:include\linux\bitmap.h |
Create Date:2022-07-27 06:38:42 |
| Last Modify:2020-03-12 14:18:49 | Copyright©Brick |
| 首页 | 函数Tree |
| 注解内核,赢得工具 | 下载SCCT | English |
函数名称:bitmap_complement
函数原型:static inline void bitmap_complement(unsigned long *dst, const unsigned long *src, unsigned int nbits)
返回类型:void
参数:
| 类型 | 参数 | 名称 |
|---|---|---|
| unsigned long * | dst | |
| const unsigned long * | src | |
| unsigned int | nbits |
| 310 | 如果The static inlines below do not handle constant nbits==0 correctly,* so make such users (should any ever turn up) call the out-of-line* versions.(nbits)则dst等于src的反 |
| 312 | 否则__bitmap_complement(dst, src, nbits) |
| 名称 | 描述 |
|---|---|
| vsscanf | vsscanf - Unformat a buffer into a list of arguments*@buf: input buffer*@fmt: format of buffer*@args: arguments |
| cpumask_complement | pumask_complement - *dstp = ~*srcp*@dstp: the cpumask result*@srcp: the input to invert |
| __nodes_complement |
| 源代码转换工具 开放的插件接口 | X |
|---|---|
| 支持:c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现:逻辑报告 代码生成和批量转换代码 |