函数逻辑报告 |
Source Code:fs\pnode.c |
Create Date:2022-07-29 10:41:42 |
Last Modify:2020-03-12 14:18:49 | Copyright©Brick |
首页 | 函数Tree |
注解内核,赢得工具 | 下载SCCT | English |
函数名称:heck if the mount 'mnt' can be unmounted successfully.*@mnt: the mount to be checked for unmount* NOTE: unmounting 'mnt' would naturally propagate to all* other mounts its parent propagates to.* Check if any of these mounts that **do not have submounts**
函数原型:int propagate_mount_busy(struct mount *mnt, int refcnt)
返回类型:int
参数:
类型 | 参数 | 名称 |
---|---|---|
struct mount * | mnt | |
int | refcnt |
373 | parent等于mnt_parent |
383 | 如果非链表为空或rn true if the refcount is greater than count则返回:1 |
405 | 返回:0 |
名称 | 描述 |
---|---|
do_umount | |
mark_mounts_for_expiry | process a list of expirable mountpoints with the intent of discarding any* mountpoints that aren't in use and haven't been touched since last we came* here |
select_submounts | Ripoff of 'select_parent()'* search the list of submounts for a given mountpoint, and move any* shrinkable submounts to the 'graveyard' list. |
may_umount | may_umount - check if a mount point is busy*@mnt: root of mount* This is called to check if a mount point has any* open files, pwds, chroots or sub mounts. If the* mount has sub mounts this will return busy* regardless of whether the sub mounts are busy. |
源代码转换工具 开放的插件接口 | X |
---|---|
支持:c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现:逻辑报告 代码生成和批量转换代码 |