函数逻辑报告 |
Source Code:fs\dcache.c |
Create Date:2022-07-29 10:37:30 |
Last Modify:2020-03-18 10:27:32 | Copyright©Brick |
首页 | 函数Tree |
注解内核,赢得工具 | 下载SCCT | English |
函数名称:path_has_submounts - check for mounts over a dentry in the* current namespace.*@parent: path to check.* Return true if the parent or its subdirectories contain* a mount point in the current namespace.
函数原型:int path_has_submounts(const struct path *parent)
返回类型:int
参数:
类型 | 参数 | 名称 |
---|---|---|
const struct path * | parent |
1404 | struct check_mount data = {mnt = mnt, mounted = 0} |
1408 | read_sequnlock_excl( & mount_lock) |
1410 | 返回:mounted |
源代码转换工具 开放的插件接口 | X |
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支持:c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现:逻辑报告 代码生成和批量转换代码 |