函数逻辑报告 |
Source Code:block\bfq-iosched.c |
Create Date:2022-07-27 19:29:57 |
Last Modify:2020-03-12 14:18:49 | Copyright©Brick |
首页 | 函数Tree |
注解内核,赢得工具 | 下载SCCT | English |
函数名称:The following function returns false either if every active queue* must receive the same share of the throughput (symmetric scenario),* or, as a special case, if bfqq must receive a share of the* throughput lower than or equal to the share that every
函数原型:static bool bfq_asymmetric_scenario(struct bfq_data *bfqd, struct bfq_queue *bfqq)
返回类型:bool
参数:
类型 | 参数 | 名称 |
---|---|---|
struct bfq_data * | bfqd | |
struct bfq_queue * | bfqq |
692 | varied_queue_weights等于非smallest_weight且非RB_EMPTY_ROOT( & rb_root)且rb_left或rb_right的值 |
名称 | 描述 |
---|---|
bfq_serv_to_charge | see the definition of bfq_async_charge_factor for details |
bfq_arm_slice_timer | |
idling_needed_for_service_guarantees | There is a case where idling does not have to be performed for* throughput concerns, but to preserve the throughput share of* the process associated with bfqq |
源代码转换工具 开放的插件接口 | X |
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支持:c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现:逻辑报告 代码生成和批量转换代码 |